What are the solutions to the equation 2x^2-12x+10=0 ?

The solutions to the equation 2x^2-12x+10=0 are x=5,x=1

Find the zeros of 2x^2-12x+10=0

The zeros of 2x^2-12x+10=0 are x=5,x=1

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2 x^{2} - 12 x + 10 = 0

x = 5, x = 1

Solution steps

2 x^{2} - 12 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 \cdot 10 = 8

x_{1, 2} = \frac{- ( - 12 ) \pm 8}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 8}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 8}{2 \cdot 2}

x = \frac{- ( - 12 ) + 8}{2 \cdot 2} : 5

x = \frac{- ( - 12 ) - 8}{2 \cdot 2} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

0.75 a = - 3

(k^{\frac{4}{5}})^{10}

m^{2} - m + 1 = 0

4 - 7 x + 10 = 15 - 6 x - 8

2 ∣ t - 3 ∣ - 3 = 7

What are the solutions to the equation 2x^2-12x+10=0 ?
The solutions to the equation 2x^2-12x+10=0 are x=5,x=1
Find the zeros of 2x^2-12x+10=0
The zeros of 2x^2-12x+10=0 are x=5,x=1