What is (m+1)/2-1/6 < m/6-(m-5)/3 ?

The solution to (m+1)/2-1/6 < m/6-(m-5)/3 is m<2

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(m+1)/2-1/6 < m/6-(m-5)/3

\frac{m + 1}{2} - \frac{1}{6} < \frac{m}{6} - \frac{m - 5}{3}

m < 2

Interval Notation

(- \infty, 2)

Solution steps

\frac{m + 1}{2} - \frac{1}{6} < \frac{m}{6} - \frac{m - 5}{3}

Multiply by LCM

3 (m + 1) - 1 < m - 2 (m - 5)

Expand

- 2 (m - 5) : - 2 m + 10

3 m + 2 < m - 2 m + 10

Add similar elements:

m - 2 m = - m

3 m + 2 < - m + 10

Expand

3 (m + 1) - 1 : 3 m + 2

3 m + 2 < - m + 10

Move

2

to the right side

3 m < - m + 8

Move

m

to the left side

4 m < 8

Divide both sides by

4

m < 2

5 x + 2 \geq - 18

2 0^{0}

(\frac{4 ^{3}}{5 ^{- 2}})^{5}

6 x + 4 = 16

\frac{4}{5} + y = 12

What is (m+1)/2-1/6 < m/6-(m-5)/3 ?
The solution to (m+1)/2-1/6 < m/6-(m-5)/3 is m<2