What is the answer to 2x^2+x-4-|2x|=0 ?

The answer to 2x^2+x-4-|2x|=0 is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4

Solve for x: 2x^2+x-4-|2x|=0

The solution is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} + x - 4 - ∣ 2 x ∣ = 0

x = \frac{- 3 - 41}{4} or x = \frac{1 + 33}{4}

Decimal Notation

x = - 2.35078 \dots, x = 1.68614 \dots

Solution steps

2 x^{2} + x - 4 - ∣ 2 x ∣ = 0

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

x = \frac{- 3 - 41}{4} or x = \frac{1 + 33}{4}

\frac{14 k ^{3} + 7 k ^{2}}{7 k ^{3} + 14 k ^{2}}

s^{2} - 2 s + 2 = 0

5 \leq 3 y + 8 < 17

x^{4} - x^{3} - x^{2} - x - 2

(3 i)^{5}

What is the answer to 2x^2+x-4-|2x|=0 ?
The answer to 2x^2+x-4-|2x|=0 is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4
Solve for x: 2x^2+x-4-|2x|=0
The solution is x=(-3-sqrt(41))/4 \lor x=(1+sqrt(33))/4