What is the answer to 0=|-2(x-1)^2+3|-4 ?

The answer to 0=|-2(x-1)^2+3|-4 is x=-sqrt(7/2)+1\lor x=sqrt(7/2)+1

Solve for x: 0=|-2(x-1)^2+3|-4

The solution is x=-sqrt(7/2)+1\lor x=sqrt(7/2)+1

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0 = - 2 (x - 1)^{2} + 3 - 4

x = - \frac{7}{2} + 1 or x = \frac{7}{2} + 1

Decimal Notation

x = - 0.87082 \dots, x = 2.87082 \dots

Solution steps

0 = - 2 (x - 1)^{2} + 3 - 4

Switch sides

- 2 (x - 1)^{2} + 3 - 4 = 0

Move

4

to the right side

- 2 (x - 1)^{2} + 3 = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

- 2 (x - 1)^{2} + 3 = - 4 or - 2 (x - 1)^{2} + 3 = 4

- 2 (x - 1)^{2} + 3 = - 4 or - 2 (x - 1)^{2} + 3 = 4

(x = - \frac{7}{2} + 1 or x = \frac{7}{2} + 1) or No Solution

x = - \frac{7}{2} + 1 or x = \frac{7}{2} + 1

x^{3} + 3 x^{2} > - x - 3

\frac{d}{d p} (p r t)

\frac{2 - 10}{2 + 10}

4^{2} - 5 x - 6

3 + (- 1)

What is the answer to 0=|-2(x-1)^2+3|-4 ?
The answer to 0=|-2(x-1)^2+3|-4 is x=-sqrt(7/2)+1\lor x=sqrt(7/2)+1
Solve for x: 0=|-2(x-1)^2+3|-4
The solution is x=-sqrt(7/2)+1\lor x=sqrt(7/2)+1