What are the solutions to the equation 8x^2+x-75=0 ?

The solutions to the equation 8x^2+x-75=0 are x=3,x=-25/8

Find the zeros of 8x^2+x-75=0

The zeros of 8x^2+x-75=0 are x=3,x=-25/8

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8 x^{2} + x - 75 = 0

x = 3, x = - \frac{25}{8}

Decimal Notation

x = 3, x = - 3.125

Solution steps

8 x^{2} + x - 75 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 8 ( - 75 )}{2 \cdot 8}

1^{2} - 4 \cdot 8 (- 75) = 49

x_{1, 2} = \frac{- 1 \pm 49}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 1 + 49}{2 \cdot 8}, x_{2} = \frac{- 1 - 49}{2 \cdot 8}

x = \frac{- 1 + 49}{2 \cdot 8} : 3

x = \frac{- 1 - 49}{2 \cdot 8} : - \frac{25}{8}

The solutions to the quadratic equation are:

x = 3, x = - \frac{25}{8}

\frac{x}{9} - \frac{x - y}{6}

x = (x - 2)^{2}

\frac{3 ^{5}}{3 ^{2}}

- 5 x^{2} + 9 + 7 x = 0

4 x^{2} - 16 x - 9

What are the solutions to the equation 8x^2+x-75=0 ?
The solutions to the equation 8x^2+x-75=0 are x=3,x=-25/8
Find the zeros of 8x^2+x-75=0
The zeros of 8x^2+x-75=0 are x=3,x=-25/8