What are the solutions to the equation 6x^2+14x+7=0 ?

The solutions to the equation 6x^2+14x+7=0 are x=(-7+sqrt(7))/6 ,x=-(7+sqrt(7))/6

Find the zeros of 6x^2+14x+7=0

The zeros of 6x^2+14x+7=0 are x=(-7+sqrt(7))/6 ,x=-(7+sqrt(7))/6

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6 x^{2} + 14 x + 7 = 0

x = \frac{- 7 + 7}{6}, x = - \frac{7 + 7}{6}

Decimal Notation

x = - 0.72570 \dots, x = - 1.60762 \dots

Solution steps

6 x^{2} + 14 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 14 \pm 1 4 ^{2} - 4 \cdot 6 \cdot 7}{2 \cdot 6}

1 4^{2} - 4 \cdot 6 \cdot 7 = 27

x_{1, 2} = \frac{- 14 \pm 2 7}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 14 + 2 7}{2 \cdot 6}, x_{2} = \frac{- 14 - 2 7}{2 \cdot 6}

x = \frac{- 14 + 2 7}{2 \cdot 6} : \frac{- 7 + 7}{6}

x = \frac{- 14 - 2 7}{2 \cdot 6} : - \frac{7 + 7}{6}

The solutions to the quadratic equation are:

x = \frac{- 7 + 7}{6}, x = - \frac{7 + 7}{6}

- 4 x + 3 = - 29

10 x^{3} - 26 x^{2} - 12 x

5 = \frac{1}{2} (7 x + 4)

(x + 1)^{2} - (x - 1)^{2} + 12 \geq 0

9 x^{2} - y^{2}

What are the solutions to the equation 6x^2+14x+7=0 ?
The solutions to the equation 6x^2+14x+7=0 are x=(-7+sqrt(7))/6 ,x=-(7+sqrt(7))/6
Find the zeros of 6x^2+14x+7=0
The zeros of 6x^2+14x+7=0 are x=(-7+sqrt(7))/6 ,x=-(7+sqrt(7))/6