What are the solutions to the equation 2x^2-13x+20=0 ?

The solutions to the equation 2x^2-13x+20=0 are x=4,x= 5/2

Find the zeros of 2x^2-13x+20=0

The zeros of 2x^2-13x+20=0 are x=4,x= 5/2

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2 x^{2} - 13 x + 20 = 0

x = 4, x = \frac{5}{2}

Decimal Notation

x = 4, x = 2.5

Solution steps

2 x^{2} - 13 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 2 \cdot 20}{2 \cdot 2}

(- 13)^{2} - 4 \cdot 2 \cdot 20 = 3

x_{1, 2} = \frac{- ( - 13 ) \pm 3}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 3}{2 \cdot 2}, x_{2} = \frac{- ( - 13 ) - 3}{2 \cdot 2}

x = \frac{- ( - 13 ) + 3}{2 \cdot 2} : 4

x = \frac{- ( - 13 ) - 3}{2 \cdot 2} : \frac{5}{2}

The solutions to the quadratic equation are:

x = 4, x = \frac{5}{2}

\frac{2}{3} \cdot \frac{3}{5}

13 x = 130

(x - 3) (x + 3)

(x^{2} - 2 x)^{2}

- \frac{3}{3}

What are the solutions to the equation 2x^2-13x+20=0 ?
The solutions to the equation 2x^2-13x+20=0 are x=4,x= 5/2
Find the zeros of 2x^2-13x+20=0
The zeros of 2x^2-13x+20=0 are x=4,x= 5/2