What are the solutions to the equation 6x^2+2x=4 ?

The solutions to the equation 6x^2+2x=4 are x= 2/3 ,x=-1

Find the zeros of 6x^2+2x=4

The zeros of 6x^2+2x=4 are x= 2/3 ,x=-1

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6 x^{2} + 2 x = 4

x = \frac{2}{3}, x = - 1

Decimal Notation

x = 0.66666 \dots, x = - 1

Solution steps

6 x^{2} + 2 x = 4

Move

4

to the left side

6 x^{2} + 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 6 ( - 4 )}{2 \cdot 6}

2^{2} - 4 \cdot 6 (- 4) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 6}, x_{2} = \frac{- 2 - 10}{2 \cdot 6}

x = \frac{- 2 + 10}{2 \cdot 6} : \frac{2}{3}

x = \frac{- 2 - 10}{2 \cdot 6} : - 1

The solutions to the quadratic equation are:

x = \frac{2}{3}, x = - 1

9 x - 10 - x = 1 + 3 (3 x - 3)

- \frac{3}{2} - \frac{5}{3}

\frac{2}{8 i}

6 + 3 ∣ 3 x + 7 ∣ = 24

2 x + 8 \leq x + 7 \leq 3 x + 10

What are the solutions to the equation 6x^2+2x=4 ?
The solutions to the equation 6x^2+2x=4 are x= 2/3 ,x=-1
Find the zeros of 6x^2+2x=4
The zeros of 6x^2+2x=4 are x= 2/3 ,x=-1