What are the solutions to the equation 5x(x-2)+7=0 ?

The solutions to the equation 5x(x-2)+7=0 are x=1+isqrt(2/5),x=1-isqrt(2/5)

Find the zeros of 5x(x-2)+7=0

The zeros of 5x(x-2)+7=0 are x=1+isqrt(2/5),x=1-isqrt(2/5)

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5 x (x - 2) + 7 = 0

x = 1 + i \frac{2}{5}, x = 1 - i \frac{2}{5}

Solution steps

5 x (x - 2) + 7 = 0

Expand

5 x (x - 2) + 7 : 5 x^{2} - 10 x + 7

5 x^{2} - 10 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

Simplify

(- 10)^{2} - 4 \cdot 5 \cdot 7 : 210 i

x_{1, 2} = \frac{- ( - 10 ) \pm 2 10 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 10 i}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 2 10 i}{2 \cdot 5}

x = \frac{- ( - 10 ) + 2 10 i}{2 \cdot 5} : 1 + i \frac{2}{5}

x = \frac{- ( - 10 ) - 2 10 i}{2 \cdot 5} : 1 - i \frac{2}{5}

The solutions to the quadratic equation are:

x = 1 + i \frac{2}{5}, x = 1 - i \frac{2}{5}

3 (x - 3)^{2} + 12 = 0

8 x^{2} - 28 x - 16

2 x \cdot 4 x^{- \frac{5}{2}}

\frac{5 x ^{2}}{6} = \frac{6}{125}

What are the solutions to the equation 5x(x-2)+7=0 ?
The solutions to the equation 5x(x-2)+7=0 are x=1+isqrt(2/5),x=1-isqrt(2/5)
Find the zeros of 5x(x-2)+7=0
The zeros of 5x(x-2)+7=0 are x=1+isqrt(2/5),x=1-isqrt(2/5)