What is 7/(9z^3y)-1/(21z^2y) ?

The solution to 7/(9z^3y)-1/(21z^2y) is (49-3z)/(63z^3y)

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simplify 7/(9z^3y)-1/(21z^2y)

simplify

\frac{7}{9 z ^{3} y} - \frac{1}{21 z ^{2} y}

\frac{49 - 3 z}{63 z ^{3} y}

Solution steps

\frac{7}{9 z ^{3} y} - \frac{1}{21 z ^{2} y}

Least Common Multiplier of

9 z^{3} y, 21 z^{2} y : 63 z^{3} y

Adjust Fractions based on the LCM

= \frac{49}{63 z ^{3} y} - \frac{3 z}{63 z ^{3} y}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{49 - 3 z}{63 z ^{3} y}

(k - 4) (k + 5) = 0

(\frac{3 x}{2})^{4}

3 x^{2} - 114 = - x

x = 1^{2}

5 x^{2} + 9 x y + 4 y^{2}

What is 7/(9z^3y)-1/(21z^2y) ?
The solution to 7/(9z^3y)-1/(21z^2y) is (49-3z)/(63z^3y)