What is factor 2x^2+7x+3 ?

The solution to factor 2x^2+7x+3 is (2x+1)(x+3)

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factor 2x^2+7x+3

factor

2 x^{2} + 7 x + 3

(2 x + 1) (x + 3)

Solution steps

2 x^{2} + 7 x + 3

Break the expression into groups

= (2 x^{2} + x) + (6 x + 3)

Factor out

x

from

2 x^{2} + x : x (2 x + 1)

Factor out

3

from

6 x + 3 : 3 (2 x + 1)

= x (2 x + 1) + 3 (2 x + 1)

Factor out common term

2 x + 1

= (2 x + 1) (x + 3)

- \frac{1}{2} x > 6

x^{2} + 11 x - 26 = 0

2 ∣ x + 1 ∣ + 3 = 9

5 x \leq 21 + 2 x or 3 (x + 1) \geq 24

\frac{5}{6} = \frac{w + 3}{7}