What are the solutions to the equation 4x^2+12x-15=5 ?

The solutions to the equation 4x^2+12x-15=5 are x=(-3+sqrt(29))/2 ,x=-(3+sqrt(29))/2

Find the zeros of 4x^2+12x-15=5

The zeros of 4x^2+12x-15=5 are x=(-3+sqrt(29))/2 ,x=-(3+sqrt(29))/2

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4 x^{2} + 12 x - 15 = 5

x = \frac{- 3 + 29}{2}, x = - \frac{3 + 29}{2}

Decimal Notation

x = 1.19258 \dots, x = - 4.19258 \dots

Solution steps

4 x^{2} + 12 x - 15 = 5

Move

5

to the left side

4 x^{2} + 12 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 4 ( - 20 )}{2 \cdot 4}

1 2^{2} - 4 \cdot 4 (- 20) = 429

x_{1, 2} = \frac{- 12 \pm 4 29}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 12 + 4 29}{2 \cdot 4}, x_{2} = \frac{- 12 - 4 29}{2 \cdot 4}

x = \frac{- 12 + 4 29}{2 \cdot 4} : \frac{- 3 + 29}{2}

x = \frac{- 12 - 4 29}{2 \cdot 4} : - \frac{3 + 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 3 + 29}{2}, x = - \frac{3 + 29}{2}

\frac{x ^{3} + 2 x ^{2}}{x ^{3} - 2 x ^{2} - 3 x}

27 x^{6} - 8 y^{6}

24 x^{2} - 2 x - 12

1.3 x - 2 - (3.3 x + 5) = 2 x + 1

7 (- 2) - 3 (7) = 11

What are the solutions to the equation 4x^2+12x-15=5 ?
The solutions to the equation 4x^2+12x-15=5 are x=(-3+sqrt(29))/2 ,x=-(3+sqrt(29))/2
Find the zeros of 4x^2+12x-15=5
The zeros of 4x^2+12x-15=5 are x=(-3+sqrt(29))/2 ,x=-(3+sqrt(29))/2