What are the solutions to the equation 0=-16t^2+95t+6 ?

The solutions to the equation 0=-16t^2+95t+6 are t=-1/16 ,t=6

Find the zeros of 0=-16t^2+95t+6

The zeros of 0=-16t^2+95t+6 are t=-1/16 ,t=6

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0 = - 16 t^{2} + 95 t + 6

t = - \frac{1}{16}, t = 6

Decimal Notation

t = - 0.0625, t = 6

Solution steps

0 = - 16 t^{2} + 95 t + 6

Switch sides

- 16 t^{2} + 95 t + 6 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 95 \pm 9 5 ^{2} - 4 ( - 16 ) \cdot 6}{2 ( - 16 )}

9 5^{2} - 4 (- 16) \cdot 6 = 97

t_{1, 2} = \frac{- 95 \pm 97}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 95 + 97}{2 ( - 16 )}, t_{2} = \frac{- 95 - 97}{2 ( - 16 )}

t = \frac{- 95 + 97}{2 ( - 16 )} : - \frac{1}{16}

t = \frac{- 95 - 97}{2 ( - 16 )} : 6

The solutions to the quadratic equation are:

t = - \frac{1}{16}, t = 6

0 = 1.5 x^{2} - 4.5 x

\frac{16}{25} x^{2} y^{2} - \frac{36}{49} y^{4}

3 x = 42

\frac{x}{15} + 3 = 4

1 - \frac{9}{16}

What are the solutions to the equation 0=-16t^2+95t+6 ?
The solutions to the equation 0=-16t^2+95t+6 are t=-1/16 ,t=6
Find the zeros of 0=-16t^2+95t+6
The zeros of 0=-16t^2+95t+6 are t=-1/16 ,t=6