What are the solutions to the equation 12x^2-x-6=0 ?

The solutions to the equation 12x^2-x-6=0 are x= 3/4 ,x=-2/3

Find the zeros of 12x^2-x-6=0

The zeros of 12x^2-x-6=0 are x= 3/4 ,x=-2/3

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12 x^{2} - x - 6 = 0

x = \frac{3}{4}, x = - \frac{2}{3}

Decimal Notation

x = 0.75, x = - 0.66666 \dots

Solution steps

12 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 12 ( - 6 )}{2 \cdot 12}

(- 1)^{2} - 4 \cdot 12 (- 6) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 12}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 12}

x = \frac{- ( - 1 ) + 17}{2 \cdot 12} : \frac{3}{4}

x = \frac{- ( - 1 ) - 17}{2 \cdot 12} : - \frac{2}{3}

The solutions to the quadratic equation are:

x = \frac{3}{4}, x = - \frac{2}{3}

5 y + 16 = 3 y + 6 y - 12

9 x^{2} + x - 9 = 0

(x + 4)^{2} = - 49

- 1 \leq 2 x - 3 < 5

2 x + 10

What are the solutions to the equation 12x^2-x-6=0 ?
The solutions to the equation 12x^2-x-6=0 are x= 3/4 ,x=-2/3
Find the zeros of 12x^2-x-6=0
The zeros of 12x^2-x-6=0 are x= 3/4 ,x=-2/3