What is (7((16(2)^3)-2))/(5^{4/5)} ?

The solution to (7((16(2)^3)-2))/(5^{4/5)} is (882)/(5^{4/5)}

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simplify (7((16(2)^3)-2))/(5^{4/5)}

simplify

\frac{7 ( ( 16 ( 2 ) ^{3} ) - 2 )}{5 ^{\frac{4}{5}}}

\frac{882}{5 ^{\frac{4}{5}}}

Solution steps

\frac{7 ( ( 16 \cdot 2 ^{3} ) - 2 )}{5 ^{\frac{4}{5}}}

Apply rule:

(a) = a

(16 \cdot 2^{3}) = 16 \cdot 2^{3}

= \frac{7 ( 16 \cdot 2 ^{3} - 2 )}{5 ^{\frac{4}{5}}}

7 (16 \cdot 2^{3} - 2) = 882

= \frac{882}{5 ^{\frac{4}{5}}}

100 x^{2} - 9 y^{2}

(x - 8)^{2} = - 2

100 b^{2} - 90 b + 20

0 \geq x \geq 10

\frac{1}{2} + \frac{3}{2}

What is (7((16(2)^3)-2))/(5^{4/5)} ?
The solution to (7((16(2)^3)-2))/(5^{4/5)} is (882)/(5^{4/5)}