What are the solutions to the equation x^2-3x+1=-1 ?

The solutions to the equation x^2-3x+1=-1 are x=2,x=1

Find the zeros of x^2-3x+1=-1

The zeros of x^2-3x+1=-1 are x=2,x=1

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x^{2} - 3 x + 1 = - 1

x = 2, x = 1

Solution steps

x^{2} - 3 x + 1 = - 1

Move

1

to the left side

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

\frac{2 x - 3}{6} - \frac{3 x - 2}{5} = - 5

3 w^{2} + 21 w + 36

9 x^{4} - 36 x^{2} = 0

- x^{2} + 2 x = 7

- 90

What are the solutions to the equation x^2-3x+1=-1 ?
The solutions to the equation x^2-3x+1=-1 are x=2,x=1
Find the zeros of x^2-3x+1=-1
The zeros of x^2-3x+1=-1 are x=2,x=1