What are the solutions to the equation x(x-5)=14 ?

The solutions to the equation x(x-5)=14 are x=7,x=-2

Find the zeros of x(x-5)=14

The zeros of x(x-5)=14 are x=7,x=-2

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x (x - 5) = 14

x = 7, x = - 2

Solution steps

x (x - 5) = 14

Expand

x (x - 5) : x^{2} - 5 x

x^{2} - 5 x = 14

Move

14

to the left side

x^{2} - 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

x = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

x = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

- \frac{1}{2} - \frac{2}{5}

(32)^{- \frac{2}{5}}

\frac{4}{9} p^{2} - 25 = 0

- 5 \geq \frac{b}{- 8}

e^{- l n (7)}

What are the solutions to the equation x(x-5)=14 ?
The solutions to the equation x(x-5)=14 are x=7,x=-2
Find the zeros of x(x-5)=14
The zeros of x(x-5)=14 are x=7,x=-2