What are the solutions to the equation 0.2*y*(1-(y/5))-0.24=0 ?

The solutions to the equation 0.2*y*(1-(y/5))-0.24=0 are y=2,y=3

Find the zeros of 0.2*y*(1-(y/5))-0.24=0

The zeros of 0.2*y*(1-(y/5))-0.24=0 are y=2,y=3

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0.2 \cdot y \cdot (1 - (\frac{y}{5})) - 0.24 = 0

y = 2, y = 3

Solution steps

0.2 y (1 - (\frac{y}{5})) - 0.24 = 0

Multiply both sides by

100

20 y (1 - \frac{y}{5}) - 24 = 0

Expand

20 y (1 - \frac{y}{5}) - 24 : 20 y - 4 y^{2} - 24

20 y - 4 y^{2} - 24 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 y^{2} + 20 y - 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 ( - 4 ) ( - 24 )}{2 ( - 4 )}

2 0^{2} - 4 (- 4) (- 24) = 4

y_{1, 2} = \frac{- 20 \pm 4}{2 ( - 4 )}

Separate the solutions

y_{1} = \frac{- 20 + 4}{2 ( - 4 )}, y_{2} = \frac{- 20 - 4}{2 ( - 4 )}

y = \frac{- 20 + 4}{2 ( - 4 )} : 2

y = \frac{- 20 - 4}{2 ( - 4 )} : 3

The solutions to the quadratic equation are:

y = 2, y = 3

(2 i)^{3}

- 5 (z + 1) = - 2 z + 10

- 1 \leq x - 3 < 4

5 x \geq - 10

What are the solutions to the equation 0.2*y*(1-(y/5))-0.24=0 ?
The solutions to the equation 0.2*y*(1-(y/5))-0.24=0 are y=2,y=3
Find the zeros of 0.2*y*(1-(y/5))-0.24=0
The zeros of 0.2*y*(1-(y/5))-0.24=0 are y=2,y=3