What are the solutions to the equation 0=x^2-7x+9 ?

The solutions to the equation 0=x^2-7x+9 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2

Find the zeros of 0=x^2-7x+9

The zeros of 0=x^2-7x+9 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2

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0 = x^{2} - 7 x + 9

x = \frac{7 + 13}{2}, x = \frac{7 - 13}{2}

Decimal Notation

x = 5.30277 \dots, x = 1.69722 \dots

Solution steps

0 = x^{2} - 7 x + 9

Switch sides

x^{2} - 7 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 9 = 13

x_{1, 2} = \frac{- ( - 7 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 13}{2 \cdot 1}

x = \frac{- ( - 7 ) + 13}{2 \cdot 1} : \frac{7 + 13}{2}

x = \frac{- ( - 7 ) - 13}{2 \cdot 1} : \frac{7 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 13}{2}, x = \frac{7 - 13}{2}

(2 x^{3} y^{7})^{- 2}

- 10 \leq - 5 x

- \frac{10}{2}

\frac{1}{2} - \frac{1}{6}

\frac{1}{- 1}

What are the solutions to the equation 0=x^2-7x+9 ?
The solutions to the equation 0=x^2-7x+9 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2
Find the zeros of 0=x^2-7x+9
The zeros of 0=x^2-7x+9 are x=(7+sqrt(13))/2 ,x=(7-sqrt(13))/2