What are the solutions to the equation x^2-14x+30=6 ?

The solutions to the equation x^2-14x+30=6 are x=12,x=2

Find the zeros of x^2-14x+30=6

The zeros of x^2-14x+30=6 are x=12,x=2

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x^{2} - 14 x + 30 = 6

x = 12, x = 2

Solution steps

x^{2} - 14 x + 30 = 6

Move

6

to the left side

x^{2} - 14 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 24 = 10

x_{1, 2} = \frac{- ( - 14 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 10}{2 \cdot 1}

x = \frac{- ( - 14 ) + 10}{2 \cdot 1} : 12

x = \frac{- ( - 14 ) - 10}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 12, x = 2

\frac{5}{2} + 8

15 x^{2} + 16 x y + 4 y^{2}

\frac{2}{3} m + \frac{5}{6} = 4

10 (n - 5) < 5 (2 n + 7)

- \frac{5}{6} + x = - \frac{11}{12}

What are the solutions to the equation x^2-14x+30=6 ?
The solutions to the equation x^2-14x+30=6 are x=12,x=2
Find the zeros of x^2-14x+30=6
The zeros of x^2-14x+30=6 are x=12,x=2