What are the solutions to the equation 6x^2+12x=90 ?

The solutions to the equation 6x^2+12x=90 are x=3,x=-5

Find the zeros of 6x^2+12x=90

The zeros of 6x^2+12x=90 are x=3,x=-5

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6 x^{2} + 12 x = 90

x = 3, x = - 5

Solution steps

6 x^{2} + 12 x = 90

Move

90

to the left side

6 x^{2} + 12 x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 6 ( - 90 )}{2 \cdot 6}

1 2^{2} - 4 \cdot 6 (- 90) = 48

x_{1, 2} = \frac{- 12 \pm 48}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 12 + 48}{2 \cdot 6}, x_{2} = \frac{- 12 - 48}{2 \cdot 6}

x = \frac{- 12 + 48}{2 \cdot 6} : 3

x = \frac{- 12 - 48}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = 3, x = - 5

\frac{2 + 5 i}{3 - i}

\frac{6}{4} - \frac{2}{4}

\frac{4}{4 + i}

144 x^{2} - 169 y^{2}

75 + 15 x \geq 140

What are the solutions to the equation 6x^2+12x=90 ?
The solutions to the equation 6x^2+12x=90 are x=3,x=-5
Find the zeros of 6x^2+12x=90
The zeros of 6x^2+12x=90 are x=3,x=-5