What are the solutions to the equation x^2-14x+24=0 ?

The solutions to the equation x^2-14x+24=0 are x=12,x=2

Find the zeros of x^2-14x+24=0

The zeros of x^2-14x+24=0 are x=12,x=2

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x^{2} - 14 x + 24 = 0

x = 12, x = 2

Solution steps

x^{2} - 14 x + 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 24 = 10

x_{1, 2} = \frac{- ( - 14 ) \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 10}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 10}{2 \cdot 1}

x = \frac{- ( - 14 ) + 10}{2 \cdot 1} : 12

x = \frac{- ( - 14 ) - 10}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 12, x = 2

5 + y = 9

n^{2} + 10 n + 7 = 0

1 - m^{6}

\frac{5 x - 105}{7 ( x + 3 )}

(24 x^{4} - 15 x^{2} + 6 x) - (10 x^{4} + 5 x^{2} - 4 x)

What are the solutions to the equation x^2-14x+24=0 ?
The solutions to the equation x^2-14x+24=0 are x=12,x=2
Find the zeros of x^2-14x+24=0
The zeros of x^2-14x+24=0 are x=12,x=2