What are the solutions to the equation 3x^2+1=7x^2 ?

The solutions to the equation 3x^2+1=7x^2 are x= 1/2 ,x=-1/2

Find the zeros of 3x^2+1=7x^2

The zeros of 3x^2+1=7x^2 are x= 1/2 ,x=-1/2

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3 x^{2} + 1 = 7 x^{2}

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.5, x = - 0.5

Solution steps

3 x^{2} + 1 = 7 x^{2}

Move

1

to the right side

3 x^{2} = 7 x^{2} - 1

Move

7 x^{2}

to the left side

- 4 x^{2} = - 1

Divide both sides by

- 4

x^{2} = \frac{1}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{4}, x = - \frac{1}{4}

\frac{1}{4} = \frac{1}{2}

- \frac{1}{4} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

∣ 2 ∣

(\frac{1}{2})^{2} - 6

6 x^{2} + 11 x - 7

- 4 - 3 n \leq - 7

What are the solutions to the equation 3x^2+1=7x^2 ?
The solutions to the equation 3x^2+1=7x^2 are x= 1/2 ,x=-1/2
Find the zeros of 3x^2+1=7x^2
The zeros of 3x^2+1=7x^2 are x= 1/2 ,x=-1/2