What are the solutions to the equation 4x^2-8x+6=0 ?

The solutions to the equation 4x^2-8x+6=0 are x=1+i(sqrt(2))/2 ,x=1-i(sqrt(2))/2

Find the zeros of 4x^2-8x+6=0

The zeros of 4x^2-8x+6=0 are x=1+i(sqrt(2))/2 ,x=1-i(sqrt(2))/2

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4 x^{2} - 8 x + 6 = 0

x = 1 + i \frac{2}{2}, x = 1 - i \frac{2}{2}

Solution steps

4 x^{2} - 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 4 \cdot 6}{2 \cdot 4}

Simplify

(- 8)^{2} - 4 \cdot 4 \cdot 6 : 42 i

x_{1, 2} = \frac{- ( - 8 ) \pm 4 2 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4 2 i}{2 \cdot 4}, x_{2} = \frac{- ( - 8 ) - 4 2 i}{2 \cdot 4}

x = \frac{- ( - 8 ) + 4 2 i}{2 \cdot 4} : 1 + i \frac{2}{2}

x = \frac{- ( - 8 ) - 4 2 i}{2 \cdot 4} : 1 - i \frac{2}{2}

The solutions to the quadratic equation are:

x = 1 + i \frac{2}{2}, x = 1 - i \frac{2}{2}

1 - (- \frac{1}{2})^{2}

42 \cdot 4

x^{2} - 3 x - 6 = 0

2 x + 5 > 13

\frac{1}{3} \cdot (- 3)

What are the solutions to the equation 4x^2-8x+6=0 ?
The solutions to the equation 4x^2-8x+6=0 are x=1+i(sqrt(2))/2 ,x=1-i(sqrt(2))/2
Find the zeros of 4x^2-8x+6=0
The zeros of 4x^2-8x+6=0 are x=1+i(sqrt(2))/2 ,x=1-i(sqrt(2))/2