What are the solutions to the equation 3x^2-5x-8=0 ?

The solutions to the equation 3x^2-5x-8=0 are x= 8/3 ,x=-1

Find the zeros of 3x^2-5x-8=0

The zeros of 3x^2-5x-8=0 are x= 8/3 ,x=-1

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3 x^{2} - 5 x - 8 = 0

x = \frac{8}{3}, x = - 1

Decimal Notation

x = 2.66666 \dots, x = - 1

Solution steps

3 x^{2} - 5 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 8) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 3}

x = \frac{- ( - 5 ) + 11}{2 \cdot 3} : \frac{8}{3}

x = \frac{- ( - 5 ) - 11}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

x = \frac{8}{3}, x = - 1

2000 (1 + \frac{0.09}{12})^{60}

\frac{x ^{2}}{4} - \frac{5 x}{2} + 4 = 0

35 k^{2} - 22 k + 7 = 4

\frac{x + 2}{2} + 2 = \frac{x + 3}{5}

10 = - 4.9 t^{2} + 18.01 t

What are the solutions to the equation 3x^2-5x-8=0 ?
The solutions to the equation 3x^2-5x-8=0 are x= 8/3 ,x=-1
Find the zeros of 3x^2-5x-8=0
The zeros of 3x^2-5x-8=0 are x= 8/3 ,x=-1