What are the solutions to the equation -4x^2+x+4=0 ?

The solutions to the equation -4x^2+x+4=0 are x=-(-1+sqrt(65))/8 ,x=(1+sqrt(65))/8

Find the zeros of -4x^2+x+4=0

The zeros of -4x^2+x+4=0 are x=-(-1+sqrt(65))/8 ,x=(1+sqrt(65))/8

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- 4 x^{2} + x + 4 = 0

x = - \frac{- 1 + 65}{8}, x = \frac{1 + 65}{8}

Decimal Notation

x = - 0.88278 \dots, x = 1.13278 \dots

Solution steps

- 4 x^{2} + x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 4 ) \cdot 4}{2 ( - 4 )}

1^{2} - 4 (- 4) \cdot 4 = 65

x_{1, 2} = \frac{- 1 \pm 65}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 1 + 65}{2 ( - 4 )}, x_{2} = \frac{- 1 - 65}{2 ( - 4 )}

x = \frac{- 1 + 65}{2 ( - 4 )} : - \frac{- 1 + 65}{8}

x = \frac{- 1 - 65}{2 ( - 4 )} : \frac{1 + 65}{8}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 65}{8}, x = \frac{1 + 65}{8}

3 x + 4 x = 3

40 - x = 4 (- 3 - 6 x) + 6

x^{2} + 20 x + 72 = 3 x

∣ 2 x ∣ = 5

x^{3} - 5 x^{2} - 5 x + 25

What are the solutions to the equation -4x^2+x+4=0 ?
The solutions to the equation -4x^2+x+4=0 are x=-(-1+sqrt(65))/8 ,x=(1+sqrt(65))/8
Find the zeros of -4x^2+x+4=0
The zeros of -4x^2+x+4=0 are x=-(-1+sqrt(65))/8 ,x=(1+sqrt(65))/8