What are the solutions to the equation 2y^2=y^2+1 ?

The solutions to the equation 2y^2=y^2+1 are y=1,y=-1

Find the zeros of 2y^2=y^2+1

The zeros of 2y^2=y^2+1 are y=1,y=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 y^{2} = y^{2} + 1

y = 1, y = - 1

Solution steps

2 y^{2} = y^{2} + 1

Move

y^{2}

to the left side

y^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = 1, y = - 1

1 = 1

- 1 = - 1

y = 1, y = - 1

u^{2} - 4 u + 4

∣ 3 x + 2 ∣ < 7

15 = 7 x + 2 x^{2}

3 (5 - 2 x) = 10 - x

r^{2} + 8 r + 20 = 0

What are the solutions to the equation 2y^2=y^2+1 ?
The solutions to the equation 2y^2=y^2+1 are y=1,y=-1
Find the zeros of 2y^2=y^2+1
The zeros of 2y^2=y^2+1 are y=1,y=-1