What are the solutions to the equation 3y^2-6y+2=0 ?

The solutions to the equation 3y^2-6y+2=0 are y=(3+sqrt(3))/3 ,y=(3-sqrt(3))/3

Find the zeros of 3y^2-6y+2=0

The zeros of 3y^2-6y+2=0 are y=(3+sqrt(3))/3 ,y=(3-sqrt(3))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 y^{2} - 6 y + 2 = 0

y = \frac{3 + 3}{3}, y = \frac{3 - 3}{3}

Decimal Notation

y = 1.57735 \dots, y = 0.42264 \dots

Solution steps

3 y^{2} - 6 y + 2 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 3 \cdot 2}{2 \cdot 3}

(- 6)^{2} - 4 \cdot 3 \cdot 2 = 23

y_{1, 2} = \frac{- ( - 6 ) \pm 2 3}{2 \cdot 3}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 3}{2 \cdot 3}, y_{2} = \frac{- ( - 6 ) - 2 3}{2 \cdot 3}

y = \frac{- ( - 6 ) + 2 3}{2 \cdot 3} : \frac{3 + 3}{3}

y = \frac{- ( - 6 ) - 2 3}{2 \cdot 3} : \frac{3 - 3}{3}

The solutions to the quadratic equation are:

y = \frac{3 + 3}{3}, y = \frac{3 - 3}{3}

\frac{( 3 ^{2} ) ( 4 ) ( 5 ^{3} )}{( 2 \times 5 ) ^{- 2}}

x^{2} - 3 x + 28 = 0

285 \cdot \frac{π}{180}

x^{4} + 5 x^{3} - 14 x^{2}

∣ 3 x - 2 ∣ > ∣ x + 2 ∣

What are the solutions to the equation 3y^2-6y+2=0 ?
The solutions to the equation 3y^2-6y+2=0 are y=(3+sqrt(3))/3 ,y=(3-sqrt(3))/3
Find the zeros of 3y^2-6y+2=0
The zeros of 3y^2-6y+2=0 are y=(3+sqrt(3))/3 ,y=(3-sqrt(3))/3