What is |3x-2|>|x+2| ?

The solution to |3x-2|>|x+2| is x 2

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|3x-2|>|x+2|

∣ 3 x - 2 ∣ > ∣ x + 2 ∣

x < 0 or x > 2

Interval Notation

(- \infty, 0) \cup (2, \infty)

Solution steps

∣ 3 x - 2 ∣ > ∣ x + 2 ∣

Find positive and negative intervals

x < - 2, - 2 \leq x < \frac{2}{3}, x \geq \frac{2}{3}

Solve the inequality for each interval

x < - 2 or - 2 \leq x < 0 or x > 2

Merge Overlapping Intervals

x < 0 or x > 2

\frac{\frac{π}{3}}{2}

- ∣ x ∣ > 4

r^{2} + 3 r - 6 = 0

1.96

(\frac{3}{7})^{2}