What is 3^{|x-2|}>9^x ?

The solution to 3^{|x-2|}>9^x is x< 2/3

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3^{|x-2|}>9^x

3^{∣ x - 2 ∣} > 9^{x}

x < \frac{2}{3}

Interval Notation

(- \infty, \frac{2}{3})

Decimal Notation

x < 0.66666 \dots

Solution steps

3^{∣ x - 2 ∣} > 9^{x}

Find positive and negative intervals

x < 2, x \geq 2

Solve the inequality for each interval

x < \frac{2}{3} or No Solution

Merge Overlapping Intervals

x < \frac{2}{3}

\frac{1}{3} (5 x - 1) \geq \frac{3}{7} (x + 5)

8 y^{3} + 14 y^{2} + 3 y

2 m^{2} - 72 m + 16

7 (14 g^{4} - 4 g + 10)

2 (y - 1) + 8 = 6 (2 y - 4)