What are the solutions to the equation 3x^2+2x=8 ?

The solutions to the equation 3x^2+2x=8 are x= 4/3 ,x=-2

Find the zeros of 3x^2+2x=8

The zeros of 3x^2+2x=8 are x= 4/3 ,x=-2

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3 x^{2} + 2 x = 8

x = \frac{4}{3}, x = - 2

Decimal Notation

x = 1.33333 \dots, x = - 2

Solution steps

3 x^{2} + 2 x = 8

Move

8

to the left side

3 x^{2} + 2 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 3 ( - 8 )}{2 \cdot 3}

2^{2} - 4 \cdot 3 (- 8) = 10

x_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 2 + 10}{2 \cdot 3}, x_{2} = \frac{- 2 - 10}{2 \cdot 3}

x = \frac{- 2 + 10}{2 \cdot 3} : \frac{4}{3}

x = \frac{- 2 - 10}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 2

ln (0.1)

\frac{x}{- 5} + 12 < 11

x + 2 \leq 4

- 2 \leq x < 7

0.3 (n - 5) = 0.4 - 0.2

What are the solutions to the equation 3x^2+2x=8 ?
The solutions to the equation 3x^2+2x=8 are x= 4/3 ,x=-2
Find the zeros of 3x^2+2x=8
The zeros of 3x^2+2x=8 are x= 4/3 ,x=-2