What are the solutions to the equation 2(m-7)^2=16 ?

The solutions to the equation 2(m-7)^2=16 are m=2sqrt(2)+7,m=-2sqrt(2)+7

Find the zeros of 2(m-7)^2=16

The zeros of 2(m-7)^2=16 are m=2sqrt(2)+7,m=-2sqrt(2)+7

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2 (m - 7)^{2} = 16

m = 22 + 7, m = - 22 + 7

Decimal Notation

m = 9.82842 \dots, m = 4.17157 \dots

Solution steps

2 (m - 7)^{2} = 16

Divide both sides by

2

(m - 7)^{2} = 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

m - 7 = 8 : m = 22 + 7

Solve

m - 7 = - 8 : m = - 22 + 7

The solutions to the quadratic equation are:

m = 22 + 7, m = - 22 + 7

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\frac{\frac{1}{4} ( \frac{1}{4} - 1 ) ( \frac{1}{4} - 2 )}{3 !}

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What are the solutions to the equation 2(m-7)^2=16 ?
The solutions to the equation 2(m-7)^2=16 are m=2sqrt(2)+7,m=-2sqrt(2)+7
Find the zeros of 2(m-7)^2=16
The zeros of 2(m-7)^2=16 are m=2sqrt(2)+7,m=-2sqrt(2)+7