What are the solutions to the equation x^2-6x+9=0 ?

The solutions to the equation x^2-6x+9=0 are x=3

Find the zeros of x^2-6x+9=0

The zeros of x^2-6x+9=0 are x=3

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x^{2} - 6 x + 9 = 0

x = 3

Solution steps

x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 6 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 6 )}{2 \cdot 1}

\frac{- ( - 6 )}{2 \cdot 1} = 3

x = 3

The solution to the quadratic equation is:

x = 3

3 x^{3} + 9 x^{2} + 5 x + 15

363

- 1 + 3

\frac{2}{9} - (- \frac{1}{2})

(x^{\frac{5}{3}})^{2}

What are the solutions to the equation x^2-6x+9=0 ?
The solutions to the equation x^2-6x+9=0 are x=3
Find the zeros of x^2-6x+9=0
The zeros of x^2-6x+9=0 are x=3