What are the solutions to the equation 4=(y-7)^2 ?

The solutions to the equation 4=(y-7)^2 are y=9,y=5

Find the zeros of 4=(y-7)^2

The zeros of 4=(y-7)^2 are y=9,y=5

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4 = (y - 7)^{2}

y = 9, y = 5

Solution steps

4 = (y - 7)^{2}

Switch sides

(y - 7)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 7 = 4 : y = 9

Solve

y - 7 = - 4 : y = 5

The solutions to the quadratic equation are:

y = 9, y = 5

- 1.8 x^{2} + 14.4 x = 0

∣ x ∣ - 5 \leq - 2

(x + 9)^{2} (x + 2) (x - 1) > 0

\frac{150}{5 ^{4}} - \frac{10}{5 ^{3}}

(x + 1) (x + 5) > 0

What are the solutions to the equation 4=(y-7)^2 ?
The solutions to the equation 4=(y-7)^2 are y=9,y=5
Find the zeros of 4=(y-7)^2
The zeros of 4=(y-7)^2 are y=9,y=5