What are the solutions to the equation sqrt(2)^2+1^2=c^2 ?

The solutions to the equation sqrt(2)^2+1^2=c^2 are c=sqrt(3),c=-sqrt(3)

Find the zeros of sqrt(2)^2+1^2=c^2

The zeros of sqrt(2)^2+1^2=c^2 are c=sqrt(3),c=-sqrt(3)

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2^{2} + 1^{2} = c^{2}

c = 3, c = - 3

Decimal Notation

c = 1.73205 \dots, c = - 1.73205 \dots

Solution steps

(2)^{2} + 1^{2} = c^{2}

Switch sides

c^{2} = (2)^{2} + 1^{2}

Simplify

(2)^{2} + 1^{2} : 3

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 3, c = - 3

x^{2} > 3

\frac{x}{2} + \frac{x}{5} > 5

4 m^{2} + 10 m n^{2}

\frac{( 3.8 )}{6}

(\frac{1}{x})^{3} (\frac{1}{x})^{5}

What are the solutions to the equation sqrt(2)^2+1^2=c^2 ?
The solutions to the equation sqrt(2)^2+1^2=c^2 are c=sqrt(3),c=-sqrt(3)
Find the zeros of sqrt(2)^2+1^2=c^2
The zeros of sqrt(2)^2+1^2=c^2 are c=sqrt(3),c=-sqrt(3)