What is (a+4)/8+(1-3a)/(12) ?

The solution to (a+4)/8+(1-3a)/(12) is (-3a+14)/(24)

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simplify (a+4)/8+(1-3a)/(12)

simplify

\frac{a + 4}{8} + \frac{1 - 3 a}{12}

\frac{- 3 a + 14}{24}

Solution steps

\frac{a + 4}{8} + \frac{1 - 3 a}{12}

Least Common Multiplier of

8, 12 : 24

Adjust Fractions based on the LCM

= \frac{( a + 4 ) \cdot 3}{24} + \frac{( 1 - 3 a ) \cdot 2}{24}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{( a + 4 ) \cdot 3 + ( 1 - 3 a ) \cdot 2}{24}

Simplify

(a + 4) \cdot 3 + (1 - 3 a) \cdot 2 : - 3 a + 14

= \frac{- 3 a + 14}{24}

(x - 1)^{2} < (x + 9)^{2}

- 36 x (- 9 x^{2} + 25) > 0

8 + 9 ∣ 5 m - 7 ∣ = 26

9 (x - 2) = 27

e^{- 4 (0)}

What is (a+4)/8+(1-3a)/(12) ?
The solution to (a+4)/8+(1-3a)/(12) is (-3a+14)/(24)