What are the solutions to the equation j^2+20j=0 ?

The solutions to the equation j^2+20j=0 are j=0,j=-20

Find the zeros of j^2+20j=0

The zeros of j^2+20j=0 are j=0,j=-20

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j^{2} + 20 j = 0

j = 0, j = - 20

Solution steps

j^{2} + 20 j = 0

Solve with the quadratic formula

j_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

2 0^{2} - 4 \cdot 1 \cdot 0 = 20

j_{1, 2} = \frac{- 20 \pm 20}{2 \cdot 1}

Separate the solutions

j_{1} = \frac{- 20 + 20}{2 \cdot 1}, j_{2} = \frac{- 20 - 20}{2 \cdot 1}

j = \frac{- 20 + 20}{2 \cdot 1} : 0

j = \frac{- 20 - 20}{2 \cdot 1} : - 20

The solutions to the quadratic equation are:

j = 0, j = - 20

4 x^{2} = 10

3 a^{2} = 147

2 x^{2} + 16 x = 0

2 x - 18 < - 6

x - 2 = 8

What are the solutions to the equation j^2+20j=0 ?
The solutions to the equation j^2+20j=0 are j=0,j=-20
Find the zeros of j^2+20j=0
The zeros of j^2+20j=0 are j=0,j=-20