What are the solutions to the equation (x+5)^2-7=0 ?

The solutions to the equation (x+5)^2-7=0 are x=sqrt(7)-5,x=-sqrt(7)-5

Find the zeros of (x+5)^2-7=0

The zeros of (x+5)^2-7=0 are x=sqrt(7)-5,x=-sqrt(7)-5

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(x + 5)^{2} - 7 = 0

x = 7 - 5, x = - 7 - 5

Decimal Notation

x = - 2.35424 \dots, x = - 7.64575 \dots

Solution steps

(x + 5)^{2} - 7 = 0

Move

7

to the right side

(x + 5)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 5 = 7 : x = 7 - 5

Solve

x + 5 = - 7 : x = - 7 - 5

The solutions to the quadratic equation are:

x = 7 - 5, x = - 7 - 5

2 x + 1 \geq 3 x - 2 (5 x - 4)

(\frac{4}{6})^{5}

- 8 (n - 4) = n - 40

(2 b + 4) - (6 + b) = - 4

4 x + 5 \leq 9

What are the solutions to the equation (x+5)^2-7=0 ?
The solutions to the equation (x+5)^2-7=0 are x=sqrt(7)-5,x=-sqrt(7)-5
Find the zeros of (x+5)^2-7=0
The zeros of (x+5)^2-7=0 are x=sqrt(7)-5,x=-sqrt(7)-5