What are the solutions to the equation (x+5)(x+3)=x+5 ?

The solutions to the equation (x+5)(x+3)=x+5 are x=-2,x=-5

Find the zeros of (x+5)(x+3)=x+5

The zeros of (x+5)(x+3)=x+5 are x=-2,x=-5

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(x + 5) (x + 3) = x + 5

x = - 2, x = - 5

Solution steps

(x + 5) (x + 3) = x + 5

Expand

(x + 5) (x + 3) : x^{2} + 8 x + 15

x^{2} + 8 x + 15 = x + 5

Move

5

to the left side

x^{2} + 8 x + 10 = x

Move

x

to the left side

x^{2} + 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 3}{2 \cdot 1}, x_{2} = \frac{- 7 - 3}{2 \cdot 1}

x = \frac{- 7 + 3}{2 \cdot 1} : - 2

x = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 2, x = - 5

a^{3} + n^{3}

\frac{x - 4}{5} \leq 2

49 x^{2} - 25

\frac{1}{3} (3)^{0}

- ∣ 10 c - 2 ∣ + 3 = - 9

What are the solutions to the equation (x+5)(x+3)=x+5 ?
The solutions to the equation (x+5)(x+3)=x+5 are x=-2,x=-5
Find the zeros of (x+5)(x+3)=x+5
The zeros of (x+5)(x+3)=x+5 are x=-2,x=-5