What are the solutions to the equation 2x^2+13x=7 ?

The solutions to the equation 2x^2+13x=7 are x= 1/2 ,x=-7

Find the zeros of 2x^2+13x=7

The zeros of 2x^2+13x=7 are x= 1/2 ,x=-7

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2 x^{2} + 13 x = 7

x = \frac{1}{2}, x = - 7

Decimal Notation

x = 0.5, x = - 7

Solution steps

2 x^{2} + 13 x = 7

Move

7

to the left side

2 x^{2} + 13 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

1 3^{2} - 4 \cdot 2 (- 7) = 15

x_{1, 2} = \frac{- 13 \pm 15}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 13 + 15}{2 \cdot 2}, x_{2} = \frac{- 13 - 15}{2 \cdot 2}

x = \frac{- 13 + 15}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 13 - 15}{2 \cdot 2} : - 7

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 7

(\frac{1}{x - 1})^{2}

(x - (2 - 5 i)) (x - (2 + 5 i))

3 - \frac{5}{3}

8 m + 5 \geq 5

What are the solutions to the equation 2x^2+13x=7 ?
The solutions to the equation 2x^2+13x=7 are x= 1/2 ,x=-7
Find the zeros of 2x^2+13x=7
The zeros of 2x^2+13x=7 are x= 1/2 ,x=-7