What are the solutions to the equation a^2-7a+10=0 ?

The solutions to the equation a^2-7a+10=0 are a=5,a=2

Find the zeros of a^2-7a+10=0

The zeros of a^2-7a+10=0 are a=5,a=2

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a^{2} - 7 a + 10 = 0

a = 5, a = 2

Solution steps

a^{2} - 7 a + 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

a_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, a_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

a = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

a = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

a = 5, a = 2

f + 8 \leq 3 and f + 9 \geq - 4

6 [x - (2 x + 3)] = 8 - 5 x

14 z^{3} - 35 z^{2} + 16 z - 40

- 4 \leq \frac{- 4 x - 2}{- 3} \leq 5

2 x - 2 y

What are the solutions to the equation a^2-7a+10=0 ?
The solutions to the equation a^2-7a+10=0 are a=5,a=2
Find the zeros of a^2-7a+10=0
The zeros of a^2-7a+10=0 are a=5,a=2