What are the solutions to the equation 25x^2-40x+80=0 ?

The solutions to the equation 25x^2-40x+80=0 are x= 4/5+i 8/5 ,x= 4/5-i 8/5

Find the zeros of 25x^2-40x+80=0

The zeros of 25x^2-40x+80=0 are x= 4/5+i 8/5 ,x= 4/5-i 8/5

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25 x^{2} - 40 x + 80 = 0

x = \frac{4}{5} + i \frac{8}{5}, x = \frac{4}{5} - i \frac{8}{5}

Solution steps

25 x^{2} - 40 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 25 \cdot 80}{2 \cdot 25}

Simplify

(- 40)^{2} - 4 \cdot 25 \cdot 80 : 80 i

x_{1, 2} = \frac{- ( - 40 ) \pm 80 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 80 i}{2 \cdot 25}, x_{2} = \frac{- ( - 40 ) - 80 i}{2 \cdot 25}

x = \frac{- ( - 40 ) + 80 i}{2 \cdot 25} : \frac{4}{5} + i \frac{8}{5}

x = \frac{- ( - 40 ) - 80 i}{2 \cdot 25} : \frac{4}{5} - i \frac{8}{5}

The solutions to the quadratic equation are:

x = \frac{4}{5} + i \frac{8}{5}, x = \frac{4}{5} - i \frac{8}{5}

x^{2} - x - 6 = 4

(x + 2)^{2} = 20

- 0.25

4 a^{3} - 7 a^{2} + 4 a - 7

y + 4 = 0

What are the solutions to the equation 25x^2-40x+80=0 ?
The solutions to the equation 25x^2-40x+80=0 are x= 4/5+i 8/5 ,x= 4/5-i 8/5
Find the zeros of 25x^2-40x+80=0
The zeros of 25x^2-40x+80=0 are x= 4/5+i 8/5 ,x= 4/5-i 8/5