What are the solutions to the equation x^2= 24/25 ?

The solutions to the equation x^2= 24/25 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5

Find the zeros of x^2= 24/25

The zeros of x^2= 24/25 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5

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x^{2} = \frac{24}{25}

x = \frac{2 6}{5}, x = - \frac{2 6}{5}

Decimal Notation

x = 0.97979 \dots, x = - 0.97979 \dots

Solution steps

x^{2} = \frac{24}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{24}{25}, x = - \frac{24}{25}

\frac{24}{25} = \frac{2 6}{5}

- \frac{24}{25} = - \frac{2 6}{5}

x = \frac{2 6}{5}, x = - \frac{2 6}{5}

2 \geq \frac{1}{a - 1} > 1

x^{2} + 2 x - 1 < 0

3 \cdot 7

[(2 d + 1)^{(\frac{1}{2})}] + [(d)^{(\frac{1}{2})}] \leq 5

7 x - 5 = 23

What are the solutions to the equation x^2= 24/25 ?
The solutions to the equation x^2= 24/25 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5
Find the zeros of x^2= 24/25
The zeros of x^2= 24/25 are x=(2sqrt(6))/5 ,x=-(2sqrt(6))/5