What are the solutions to the equation 9x^2=6x+3 ?

The solutions to the equation 9x^2=6x+3 are x=1,x=-1/3

Find the zeros of 9x^2=6x+3

The zeros of 9x^2=6x+3 are x=1,x=-1/3

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9 x^{2} = 6 x + 3

x = 1, x = - \frac{1}{3}

Decimal Notation

x = 1, x = - 0.33333 \dots

Solution steps

9 x^{2} = 6 x + 3

Move

3

to the left side

9 x^{2} - 3 = 6 x

Move

6 x

to the left side

9 x^{2} - 3 - 6 x = 0

Write in the standard form

a x^{2} + b x + c = 0

9 x^{2} - 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 9 ( - 3 )}{2 \cdot 9}

(- 6)^{2} - 4 \cdot 9 (- 3) = 12

x_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 12}{2 \cdot 9}, x_{2} = \frac{- ( - 6 ) - 12}{2 \cdot 9}

x = \frac{- ( - 6 ) + 12}{2 \cdot 9} : 1

x = \frac{- ( - 6 ) - 12}{2 \cdot 9} : - \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{3}

a^{7} a^{12}

\frac{2}{3} + \frac{1}{5}

x^{2} + x = 132

74 y - 8 - 78 y = - 4 y - 8

\frac{4}{7} (\frac{2}{3})^{2} + \frac{8}{9}

What are the solutions to the equation 9x^2=6x+3 ?
The solutions to the equation 9x^2=6x+3 are x=1,x=-1/3
Find the zeros of 9x^2=6x+3
The zeros of 9x^2=6x+3 are x=1,x=-1/3