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Popular >

3|x-1|+2<= 8

Solution

3 ∣ x - 1 ∣ + 2 \leq 8

Solution

- 1 \leq x \leq 3

+1

Solution steps

3 ∣ x - 1 ∣ + 2 \leq 8

Move

2

to the right side

3 ∣ x - 1 ∣ \leq 6

Divide both sides by

3

∣ x - 1 ∣ \leq 2

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 2 \leq x - 1 \leq 2

x - 1 \geq - 2 and x - 1 \leq 2

x \geq - 1 and x \leq 3

Merge Overlapping Intervals

- 1 \leq x \leq 3

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3 x^{2} - 34 x + 11

3 x^{2} - 6 x + 2 = 0

simplify-1.2(2)^2+9.6(2)simplify

- 1.2 (2)^{2} + 9.6 (2)

9 = 3 + \frac{k}{3}

Frequently Asked Questions (FAQ)

What is 3|x-1|+2<= 8 ?
The solution to 3|x-1|+2<= 8 is -1<= x<= 3