What are the solutions to the equation x^2+2x-e^3=0 ?

The solutions to the equation x^2+2x-e^3=0 are x=(-2+sqrt(4+4e^3))/2 ,x=(-2-sqrt(4+4e^3))/2

Find the zeros of x^2+2x-e^3=0

The zeros of x^2+2x-e^3=0 are x=(-2+sqrt(4+4e^3))/2 ,x=(-2-sqrt(4+4e^3))/2

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x^{2} + 2 x - e^{3} = 0

x = \frac{- 2 + 4 + 4 e ^{3}}{2}, x = \frac{- 2 - 4 + 4 e ^{3}}{2}

Decimal Notation

x = 3.59189 \dots, x = - 5.59189 \dots

Solution steps

x^{2} + 2 x - e^{3} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - e ^{3} )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- e^{3}) = 4 + 4 e^{3}

x_{1, 2} = \frac{- 2 \pm 4 + 4 e ^{3}}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 4 + 4 e ^{3}}{2 \cdot 1}, x_{2} = \frac{- 2 - 4 + 4 e ^{3}}{2 \cdot 1}

x = \frac{- 2 + 4 + 4 e ^{3}}{2 \cdot 1} : \frac{- 2 + 4 + 4 e ^{3}}{2}

x = \frac{- 2 - 4 + 4 e ^{3}}{2 \cdot 1} : \frac{- 2 - 4 + 4 e ^{3}}{2}

The solutions to the quadratic equation are:

x = \frac{- 2 + 4 + 4 e ^{3}}{2}, x = \frac{- 2 - 4 + 4 e ^{3}}{2}

3 x - 10 = 5

2 - 4 x > 6

(\frac{1}{2})^{2} - 3

3^{- 2} = \frac{1}{9}

5 x^{2} - x + 5 = 6 x + 3

What are the solutions to the equation x^2+2x-e^3=0 ?
The solutions to the equation x^2+2x-e^3=0 are x=(-2+sqrt(4+4e^3))/2 ,x=(-2-sqrt(4+4e^3))/2
Find the zeros of x^2+2x-e^3=0
The zeros of x^2+2x-e^3=0 are x=(-2+sqrt(4+4e^3))/2 ,x=(-2-sqrt(4+4e^3))/2