What are the solutions to the equation 6x^2+22x-40=0 ?

The solutions to the equation 6x^2+22x-40=0 are x= 4/3 ,x=-5

Find the zeros of 6x^2+22x-40=0

The zeros of 6x^2+22x-40=0 are x= 4/3 ,x=-5

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6 x^{2} + 22 x - 40 = 0

x = \frac{4}{3}, x = - 5

Decimal Notation

x = 1.33333 \dots, x = - 5

Solution steps

6 x^{2} + 22 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 6 ( - 40 )}{2 \cdot 6}

2 2^{2} - 4 \cdot 6 (- 40) = 38

x_{1, 2} = \frac{- 22 \pm 38}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 22 + 38}{2 \cdot 6}, x_{2} = \frac{- 22 - 38}{2 \cdot 6}

x = \frac{- 22 + 38}{2 \cdot 6} : \frac{4}{3}

x = \frac{- 22 - 38}{2 \cdot 6} : - 5

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - 5

- 2 < x < 7

12 b^{2} - 44 b + 35

\frac{x}{6} + \frac{x}{2} + \frac{x}{3} = 180

x^{5} y^{4} + y^{5}

(\frac{2 ^{\frac{1}{2}}}{8})^{2}

What are the solutions to the equation 6x^2+22x-40=0 ?
The solutions to the equation 6x^2+22x-40=0 are x= 4/3 ,x=-5
Find the zeros of 6x^2+22x-40=0
The zeros of 6x^2+22x-40=0 are x= 4/3 ,x=-5