What are the solutions to the equation x^2-4x-12=84 ?

The solutions to the equation x^2-4x-12=84 are x=12,x=-8

Find the zeros of x^2-4x-12=84

The zeros of x^2-4x-12=84 are x=12,x=-8

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x^{2} - 4 x - 12 = 84

x = 12, x = - 8

Solution steps

x^{2} - 4 x - 12 = 84

Move

84

to the left side

x^{2} - 4 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 96 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 96) = 20

x_{1, 2} = \frac{- ( - 4 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 20}{2 \cdot 1}

x = \frac{- ( - 4 ) + 20}{2 \cdot 1} : 12

x = \frac{- ( - 4 ) - 20}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 12, x = - 8

7 (x - 4)^{2} - 3 (x + 5)^{2} = 4 (x + 1) (x - 1) + 3

(4 9^{3})^{\frac{1}{6}}

2 x - 3 (1 - x) + 7 = - 5 x

2 x (3 x - 5) + 7 x (1 - x) = - 10

What are the solutions to the equation x^2-4x-12=84 ?
The solutions to the equation x^2-4x-12=84 are x=12,x=-8
Find the zeros of x^2-4x-12=84
The zeros of x^2-4x-12=84 are x=12,x=-8