What is the answer to 7(x-4)^2-3(x+5)^2=4(x+1)(x-1)+3 ?

The answer to 7(x-4)^2-3(x+5)^2=4(x+1)(x-1)+3 is x= 19/43

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7(x-4)^2-3(x+5)^2=4(x+1)(x-1)+3

7 (x - 4)^{2} - 3 (x + 5)^{2} = 4 (x + 1) (x - 1) + 3

x = \frac{19}{43}

Decimal Notation

x = 0.44186 \dots

Solution steps

7 (x - 4)^{2} - 3 (x + 5)^{2} = 4 (x + 1) (x - 1) + 3

Expand

7 (x - 4)^{2} - 3 (x + 5)^{2} : 4 x^{2} - 86 x + 37

Expand

4 (x + 1) (x - 1) + 3 : 4 x^{2} - 1

4 x^{2} - 86 x + 37 = 4 x^{2} - 1

Move

37

to the right side

4 x^{2} - 86 x = 4 x^{2} - 38

Move

4 x^{2}

to the left side

- 86 x = - 38

Divide both sides by

- 86

x = \frac{19}{43}

(4 9^{3})^{\frac{1}{6}}

2 x - 3 (1 - x) + 7 = - 5 x

2 x (3 x - 5) + 7 x (1 - x) = - 10

x^{2} - \frac{3}{2} x + 3 = 0

What is the answer to 7(x-4)^2-3(x+5)^2=4(x+1)(x-1)+3 ?
The answer to 7(x-4)^2-3(x+5)^2=4(x+1)(x-1)+3 is x= 19/43
Solve for x: 7(x-4)^2-3(x+5)^2=4(x+1)(x-1)+3
The solution is x= 19/43