What are the solutions to the equation x^2-3/2 x+3=0 ?

The solutions to the equation x^2-3/2 x+3=0 are x= 3/4+i(sqrt(39))/4 ,x= 3/4-i(sqrt(39))/4

Find the zeros of x^2-3/2 x+3=0

The zeros of x^2-3/2 x+3=0 are x= 3/4+i(sqrt(39))/4 ,x= 3/4-i(sqrt(39))/4

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x^{2} - \frac{3}{2} x + 3 = 0

x = \frac{3}{4} + i \frac{39}{4}, x = \frac{3}{4} - i \frac{39}{4}

Solution steps

x^{2} - \frac{3}{2} x + 3 = 0

Multiply both sides by

2

2 x^{2} - 3 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 3)^{2} - 4 \cdot 2 \cdot 6 : 39 i

x_{1, 2} = \frac{- ( - 3 ) \pm 39 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 39 i}{2 \cdot 2}, x_{2} = \frac{- ( - 3 ) - 39 i}{2 \cdot 2}

x = \frac{- ( - 3 ) + 39 i}{2 \cdot 2} : \frac{3}{4} + i \frac{39}{4}

x = \frac{- ( - 3 ) - 39 i}{2 \cdot 2} : \frac{3}{4} - i \frac{39}{4}

The solutions to the quadratic equation are:

x = \frac{3}{4} + i \frac{39}{4}, x = \frac{3}{4} - i \frac{39}{4}

x^{- \frac{3}{2}}

8 t = - 2

5 = v - 6

\frac{( 2 x - 1 )}{x + 2} \leq 4

∣ x - 3 ∣ \leq ∣ x + 2 ∣

What are the solutions to the equation x^2-3/2 x+3=0 ?
The solutions to the equation x^2-3/2 x+3=0 are x= 3/4+i(sqrt(39))/4 ,x= 3/4-i(sqrt(39))/4
Find the zeros of x^2-3/2 x+3=0
The zeros of x^2-3/2 x+3=0 are x= 3/4+i(sqrt(39))/4 ,x= 3/4-i(sqrt(39))/4